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الكلية كلية هندسة المواد
القسم قسم هندسة المعادن
المرحلة 2
أستاذ المادة جاسم محمد سلمان المرشدي
18/12/2015 15:54:37
phase – a region in a material that differs in structure and function from other regions phase diagrams – graphical representations of what phases are present in a materials system at different conditions (temperature, pressure and composition) (1) phase diagrams of pure substances pure substance exist as solid, liquid and vapor phases depending on the conditions of temperature and pressure pressure-temperature (PT) phase diagram 1 5. phase diagrams phase – a region in a material that differs in structure and function from other regions phase diagrams – graphical representations of what phases are present in a materials system at different conditions (temperature, pressure and composition) (1) phase diagrams of pure substances pure substance exist as solid, liquid and vapor phases depending on the conditions of temperature and pressure pressure-temperature (PT) phase diagram • water two-phase equilibrium line triple point 4.579 torr 2 • iron three distinct solid phases: ? Fe, ? Fe, ? Fe three triple points (2) Gibbs phase rule P + F = C + 2 P: number of phases that coexist in a system C: number of components F: degrees of freedom ex. water triple point 3 + F = 1 + 2 F = 0 L-S freezing curve 2 + F = 1 + 2 F = 1 degrees of freedom indicate number of variables that can be changed without changing number of phases 3 (3) cooling curves used to determine phase transition temperature temperature vs. time data of cooling molten material is recorded and plotted BC – plateaue or region of thermal arrest • cooling curve for pure Fe undercooling freezing polymorphic transformation 4 (4) binary isomorphous alloy systems binary alloy – a mixture of two metals isomorphous system – two elements completely soluble in each other in liquid and solid state usually satisfy one or more Hume-Rothery solid solubility rules • copper-nickel system liquidus solidus composition of liquid + solid phases at any temperature can be determined by drawing a tie line ex. at 1300oC an alloy of 53% Ni + 47% Cu in liquid + solid phase composition of liquid phase: 45% Ni composition of solid phase: 58% Ni 5 binary equilibrium phase diagram cooling curves equilibrium phase diagram points of change of slope of cooling curves (thermal arrests) are noted for metal alloys, solidification begins at a specific temperature (L) and ends at a lower temperature (S) the freezing temperature of a metal alloy is the temperature at which the solidification process is complete 6 (5) lever rule the lever rule gives the weight % of phases in any two phase regions Xs + Xl = 1 Xs = 1 - Xl consider 1 g of alloy, weight balance of B: (1 g)(%w0) = (1g)(Xl)(%wl) + (1g)(Xs)(%ws) w0 = Xlwl + Xsws w0 = Xlwl + (1 - Xl)ws w0 = (1 - Xs)wl + Xsws w0 = wl - Xswl + Xsws w0 – w1 Wt fraction of solid phase = Xs = ———— ws – w1 w0 = Xlwl + ws - Xlws ws – w0 Wt fraction of liquid phase = Xl = ———— ws – w1 7 the weight fraction of liquid phase is the ratio of OS/LS the weight fraction of solid phase is the ratio of LO/LS ex. Cu-Ni alloy contains 47 wt% Cu and 53 wt% Ni at 1300oC a. what is the wt% of Cu in liquid and in solid phases? b. what wt% of this alloy is liquid? a. from the phase diagram, wt% of Ni in liquid is 45% and in solid is 58% wt% of Cu in liquid is 55% and in solid is 42% b. ws – w0 58 - 53 Xl = ———— = ———— = 5/13 = 0.38 38% ws – w1 58 - 45 w0 – wl 53 - 45 Xs = ———— = ———— = 8/13 = 0.62 62% ws – w1 58 - 45 8 ex. calculate the wt% liquid and solid for Ag-Pd phase diagram shown below at 1200oC and 70 wt% Ag. ws – w0 64 - 70 Xl = ———— = ———— = 6/10 = 0.6 60% ws – w1 64 - 74 w0 – wl 70 - 74 Xs = ———— = ———— = 4/10 = 0.4 40% ws – w1 64 - 74 9 (6) nonequilibrium solidification of alloys slowly solidified alloys usually have a cored structure 70% Cu-30% Ni alloy rapid cooling (nonequilibrium) delays solidification homogenization: as-cast ingots are heated to elevated temperature to accelerate solid-state diffusion and to eliminate the cored structure temperature of homogenization must be lower than lowest melting point of any of the alloy components 10 (7) binary eutectic alloy systems in some binary alloy systems, components have limited solid solubility – eutectic system ex. Pb-Sn system • terminal solid solutions with restricted solid solubility ? (Pb-rich) and ? (Sn-rich) phases • eutectic composition freezes at lower temperature than all other compositions, this lowest temperature is called eutectic temperature 11 eutectic reaction eutectic temperature liquid ? solid solution + ? solid solution cooling eutectic reaction is an invariant reaction – degree of freedom F = 0 • slow cooling of a Pb-Sn alloy of eutectic composition 12 • slow cooling of 60% Pb – 40% Sn alloy a. liquid at 300oC b. at about 245oC first solid solution ? (12% Sn) forms – primary or proeutectic ? c. slightly above 183oC composition of alpha follows solidus and composition of Sn varies from 12% to 19.2%, composition of liquid phase varies from 40% to 61.9% d. at eutectic temperature, all the remaining liquid solidifies 13 ex. make phase analysis at the following points in Pb-Sn phase diagram: (a) at eutectic composition just below 183oC (b) point c at 40% Sn and 230oC (c) point d at 40% Sn and 183oC + ?T (d) point e at 40% Sn and 183oC - ?T (a) ? phase (19.2% Sn) + ? phase (97.5% Sn) 97.5 – 61.9 61.9 – 19.2 wt% (?) = ————— wt% (?) = ————— 97.5 – 19.2 97.5 – 19.2 = 45.5% = 54.5% (b) ? phase (15% Sn) + liquid (48% Sn) 48 – 40 40 – 15 wt% (?) = ———— wt% (L) = ———— 48 – 15 48 – 15 = 24% = 76% (c) ? phase (19.2% Sn) + liquid (61.9% Sn) 61.9 – 40 40 – 19.2 wt% (?) = ————— wt% (L) = ————— 61.9 – 19.2 61.9 – 19.2 = 51% = 49% (d) ? phase (19.2% Sn) + ? phase (97.5% Sn) 97.5 – 40 40 – 19.2 wt% (?) = ————— wt% (?) = ————— 97.5 – 19.2 97.5 – 19.2 = 73% = 27% 14 ex. an alloy of 70% Pb + 30% Sn is slowly cooled from 300oC, calculate the following: (a) wt% of the liquid and proeutectic ? form at 250oC (b) wt% of the liquid + proeutectic ? form just above eutectic temperature (183oC) (c) wt% of the ? and ? phases formed by the eutectic reaction (a) ? phase (12% Sn) + liquid(40% Sn) 40 – 30 30 – 12 wt% (?) = ———— wt% (L) = ———— 40 – 12 40 – 12 = 36% = 64% (b) ? phase (19.2% Sn) + liquid (61.9% Sn) 61.9 – 30 30 – 19.2 wt% (?) = ————— wt% (L) = ————— 61.9 – 19.2 61.9 – 19.2 = 74.7% = 25.3% (c) ? phase (19.2% Sn) + ? phase (97.5% Sn) 97.5 – 30 30 – 19.2 wt% (?) = ————— wt% (?) = ————— 97.5 – 19.2 97.5 – 19.2 = 86.2% = 13.8% 15 ex. a Pb-Sn alloy contains 64 wt% proeutectic ? and 36 wt% eutectic ? + ? at 183oC - ?T calculate the average composition of this alloy assume x wt% Sn in this alloy since 64 wt% proeutectic ? exists, the alloy must be hypoeutectic and 19.2 < x < 61.9 61.9 – x wt% = ————— = 64% 61.9 – 19.2 x = 34.6 this alloy consists of 34.6 wt% Sn and 65.4 wt% Pb • in a binary eutectic reaction two solid phases (? and ?) can have various morphologies • structure depends on factors like minimization of free energy at ? /? interface • manner in which two phases nucleate and grow also affects structures ex. lamellar eutectic structure of Pb-Sn alloy 16 (8) binary peritectic alloy system peritectic reaction – liquid phase reacts with a solid phase to form a new and different solid phase liquid + ? ? cooling peritectic reaction occurs when a slowly cooled alloy ex. Fe-Ni phase diagram ? phase – Ni in BCC-Fe ? phase – Ni in FCC-Fe Fe-4.3 wt% Ni passes through peritectic temperature of 1517oC 1517oC liquid (5.4 wt% Ni) + ? (4.0 wt% Ni) ? (4.3 wt% Ni) cooling 17 ex. Pt-Ag phase diagram the peritectic reaction occurs at 42.4 wt% Ag and 1186oC ex. make phase analysis at the following: a. at 42.4% Ag and 14000C b. at 42.4% Ag and 11860C + ?T c. at 42.4% Ag and 11860C ? ?T d. at 60% Ag and 1150oC a. phases present liquid ? composition 55% Ag 7%Ag amount of phases 42.4 –7 55-42.4 ???? ???? 55 – 7 55 - 7 = 74% = 26% 18 b. phases present liquid ? composition 66.3% Ag 10.5%Ag amount of phases 42.4 – 10.5 66.3 – 42.4 ????? ????? 66.3 – 10.5 66.3 – 10.5 = 57% =43% c. phase present ? only composition 42.4% Ag amount of phase 100% d. phases present liquid ? composition 77% Ag 48%Ag amount of phases 60 – 48 77-60 ??? ????? 77 - 48 77 – 48 = 41% = 59% very slow cooling of an alloy of peritectic composition through the peritectic temperature 19 surrounding or encasement – during rapid solidification of alloy through peritectic reaction, the ? phase created surrounds primary ? ? creates diffusion barrier resulting in coring cast 60% Ag-40% Pt hyperperitctic alloy 20 (9) binary monotectic systems monotectic reaction – liquid phase transforms into solid phase and another liquid cooling L1 ? + L2 two liquids are immiscible ex. Cu-Pb system at 955oC and 36% Pb Cu-rich portion Pb-rich portion 21 (10) invariant reactions zero degree of freedom at the reaction points 22 (11) phase diagrams with intermediate phases and compounds terminal phases – phases occur at the end of phase diagrams intermediate phases – phases occur in a composition range inside phase diagram. ex. Cu-Zn diagram has both terminal and intermediate phases. • ? and ? – terminal phases • ?, ?, ?, ? – intermediate phases • five invariant peritectic points + one eutectic point 23 ex. Al2O2 – SiO2 system an intermediate phase called mullite is formed, which includes the compound 3Al2O3.2SiO2 24 in some phase diagrams, intermediate compound are formed – stoichiometric percent ionic/covalent bond depends on electronegativeness ex. Mg-Ni phase diagram contains two intermetallic compounds: MgNi2 - congruently melting compound Mg2Ni - incongruently melting compound 25 (12) ternary phase diagrams three components phase diagrams constructed by using a equilateral triangle as base • pure components at each end of triangle binary alloy composition represented on edges • temperature can be represented as uniform throughout the whole diagram – isothermal section to determine the composition of a ternary alloy: • draw a perpendicular line from a pure metal corner to the side of the triangle opposite that corner • measure the distance from the side to the corner along the perpendicular line 26 ex. determine the wt% of metals A, B, C for ternary alloy at points x and yon the following phase diagram draw three perpendicular lines AD, BE, CF for point x (i) on AD line 40% A (ii) on BE line 40% B (iii) on CF line 20% C for point y (i) on AD line 20% A (ii) on BE line 30% B (iii) on CF line 50% C 27 ex. Fe-Cr-Ni phase diagrams. • isothermal reaction at 650oC for this system • the most important stainless steel has a composition essentially of 74% Fe, 18% Cr, and 8% Ni
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